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5w^2+7w-450=0
a = 5; b = 7; c = -450;
Δ = b2-4ac
Δ = 72-4·5·(-450)
Δ = 9049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{9049}}{2*5}=\frac{-7-\sqrt{9049}}{10} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{9049}}{2*5}=\frac{-7+\sqrt{9049}}{10} $
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